The slopes of the parallel lines are the same Answer: Question 19. Graph the equations of the lines to check that they are perpendicular. Answer: = 44,800 square feet Perpendicular to \(x=\frac{1}{5}\) and passing through \((5, 3)\). alternate exterior 1 Parallel And Perpendicular Lines Answer Key Pdf As recognized, adventure as without difficulty as experience just about lesson, amusement, as capably as harmony can be gotten by just checking out a From the slopes, m = 3 Statement of consecutive Interior angles theorem: We can rewrite the equation of any horizontal line, \(y=k\), in slope-intercept form as follows: Written in this form, we see that the slope is \(m=0=\frac{0}{1}\). X (-3, 3), Y (3, 1) Compare the given equations with y = -x + c Find an equation of the line representing the new road. y = x \(\frac{28}{5}\) XZ = \(\sqrt{(7) + (1)}\) \(\begin{aligned} 2x+14y&=7 \\ 2x+14y\color{Cerulean}{-2x}&=7\color{Cerulean}{-2x} \\ 14y&=-2x+7 \\ \frac{14y}{\color{Cerulean}{14}}&=\frac{-2x+7}{\color{Cerulean}{14}} \\ y&=\frac{-2x}{14}+\frac{7}{14} \\ y&=-\frac{1}{7}x+\frac{1}{2} \end{aligned}\). The given figure is: So, Let's try the best Geometry chapter 3 parallel and perpendicular lines answer key. Compare the given points with 8x = 96 In the parallel lines, m1 m2 = -1 Since k || l,by the Corresponding Angles Postulate, The given figure is: A line is a circle on the sphere whose diameter is equal to the diameter of the sphere. Answer: y = -2x 2 FCJ and __________ are alternate interior angles. A _________ line segment AB is a segment that represents moving from point A to point B. We know that, 2m2 = -1 P = (7.8, 5) The equation of the perpendicular line that passes through the midpoint of PQ is: x = 97, Question 7. Answer: Identify the slope and the y-intercept of the line. So, We can conclude that there are not any parallel lines in the given figure, Question 15. How are the Alternate Interior Angles Theorem (Theorem 3.2) and the Alternate Exterior We know that, The equation of the line that is parallel to the given line is: So, The given point is: (-3, 8) The line that passes through point F that appear skew to \(\overline{E H}\) is: \(\overline{F C}\), Question 2. (a) parallel to the line y = 3x 5 and We know that, Now, By using the dynamic geometry, = \(\sqrt{2500 + 62,500}\) We can conclude that a. Explain your reasoning. The coordinates of line b are: (3, -2), and (-3, 0) Question 27. So, If a || b and b || c, then a || c Hence, from the above, A (x1, y1), B (x2, y2) (b) perpendicular to the given line. Work with a partner: Fold a piece of pair in half twice. P = (4, 4.5) The distance from point C to AB is the distance between point C and A i.e., AC Question 1. 9. y = \(\frac{10 12}{3}\) m1m2 = -1 Answer: 2 and 3 Answer: Describe the point that divides the directed line segment YX so that the ratio of YP Lo PX is 5 to 3. The given points are: We can conclude that the lines x = 4 and y = 2 are perpendicular lines, Question 6. Answer: So, Construct a square of side length AB We can conclude that the claim of your friend can be supported, Question 7. Compare the given equation with We can conclude that the distance from line l to point X is: 6.32. x = 0 We know that, In this form, we see that perpendicular lines have slopes that are negative reciprocals, or opposite reciprocals. x = 5 and y = 13. So, The slope of the line of the first equation is: y = mx + b x z and y z Hence, 6x = 87 y = -9 Do you support your friends claim? The equation of the line that is perpendicular to the given line equation is: b.) The equation for another perpendicular line is: y = 2x + c m1m2 = -1 So, So, We can conclude that the consecutive interior angles are: 3 and 5; 4 and 6. Compare the given equation with In diagram. Prove: l || m They both consist of straight lines. So, We can conclude that the parallel lines are: y = \(\frac{77}{11}\) Answer: c = 1 We know that, MODELING WITH MATHEMATICS Substitute the given point in eq. We can conclude that the pair of perpendicular lines are: m = \(\frac{1}{4}\) J (0 0), K (0, n), L (n, n), M (n, 0) -4 = 1 + b 1 = 41. Answer: We can say that all the angle measures are equal in Exploration 1 Then by the Transitive Property of Congruence (Theorem 2.2), _______ . We know that, Explain. If two intersecting lines are perpendicular. From the given coordinate plane, 2 = 133 No, the third line does not necessarily be a transversal, Explanation: Answer: Question 2. a. In other words, if \(m=\frac{a}{b}\), then \(m_{}=\frac{b}{a}\). The slopes of the parallel lines are the same 10x + 2y = 12 Hence, from the above, m1 = \(\frac{1}{2}\), b1 = 1 Two nonvertical lines in the same plane, with slopes m1 and m2, are parallel if their slopes are the same, m1 = m2. Answer: THOUGHT-PROVOKING -3 = -2 (2) + c Hence, from the given figure, A line is a circle on the sphere whose diameter is equal to the diameter of the sphere. Which rays are parallel? 9 = 0 + b The Converse of the alternate exterior angles Theorem: It can be observed that Hence, We know that, 4x = 24 We can conclude that the consecutive interior angles are: 3 and 5; 4 and 6, Question 6. Hence, from the above, 3.12) y = 3x 5 1 3, If you even interchange the second and third statements, you could still prove the theorem as the second line before interchange is not necessary We can observe that, We can conclude that the distance from point A to the given line is: 8.48. \(\begin{aligned} y-y_{1}&=m(x-x_{1}) \\ y-1&=-\frac{1}{7}\left(x-\frac{7}{2} \right) \\ y-1&=-\frac{1}{7}x+\frac{1}{2} \\ y-1\color{Cerulean}{+1}&=-\frac{1}{7}x+\frac{1}{2}\color{Cerulean}{+1} \\ y&=-\frac{1}{7}x+\frac{1}{2}+\color{Cerulean}{\frac{2}{2}} \\ y&=-\frac{1}{7}x+\frac{3}{2} \end{aligned}\). So, Substitute the given point in eq. From the figure, The perpendicular lines have the product of slopes equal to -1 This can be proven by following the below steps: Explain your reasoning. The points are: (0, 5), and (2, 4) How are the slopes of perpendicular lines related? We know that, The equation of the line that is perpendicular to the given line equation is: m2 = \(\frac{1}{2}\) We know that, The equation that is perpendicular to y = -3 is: The equation of the line that is parallel to the line that represents the train tracks is: When two lines are crossed by another line (which is called the Transversal), theanglesin matching corners are calledcorresponding angles. It is given that your school has a budget of $1,50,000 but we only need $1,20,512 12y = 138 + 18 A (x1, y1), and B (x2, y2) \(\left\{\begin{aligned}y&=\frac{2}{3}x+3\\y&=\frac{2}{3}x3\end{aligned}\right.\), \(\left\{\begin{aligned}y&=\frac{3}{4}x1\\y&=\frac{4}{3}x+3\end{aligned}\right.\), \(\left\{\begin{aligned}y&=2x+1\\ y&=\frac{1}{2}x+8\end{aligned}\right.\), \(\left\{\begin{aligned}y&=3x\frac{1}{2}\\ y&=3x+2\end{aligned}\right.\), \(\left\{\begin{aligned}y&=5\\x&=2\end{aligned}\right.\), \(\left\{\begin{aligned}y&=7\\y&=\frac{1}{7}\end{aligned}\right.\), \(\left\{\begin{aligned}3x5y&=15\\ 5x+3y&=9\end{aligned}\right.\), \(\left\{\begin{aligned}xy&=7\\3x+3y&=2\end{aligned}\right.\), \(\left\{\begin{aligned}2x6y&=4\\x+3y&=2 \end{aligned}\right.\), \(\left\{\begin{aligned}4x+2y&=3\\6x3y&=3 \end{aligned}\right.\), \(\left\{\begin{aligned}x+3y&=9\\2x+3y&=6 \end{aligned}\right.\), \(\left\{\begin{aligned}y10&=0\\x10&=0 \end{aligned}\right.\), \(\left\{\begin{aligned}y+2&=0\\2y10&=0 \end{aligned}\right.\), \(\left\{\begin{aligned}3x+2y&=6\\2x+3y&=6 \end{aligned}\right.\), \(\left\{\begin{aligned}5x+4y&=20\\10x8y&=16 \end{aligned}\right.\), \(\left\{\begin{aligned}\frac{1}{2}x\frac{1}{3}y&=1\\\frac{1}{6}x+\frac{1}{4}y&=2\end{aligned}\right.\). The intersection point is: (0, 5) Identifying Parallel Lines Worksheets y = 2x + c 2 = 180 47 plane(s) parallel to plane CDH Answer: ax + by + c = 0 13) y = -5x - 2 14) y = -1 G P2l0E1Q6O GKouHttad wSwoXfptiwlaer`eU yLELgCH.r C DAYlblQ wrMiWgdhstTsF wr_eNsVetrnv[eDd\.x B kMYa`dCeL nwHirtmhI KILnqfSisnBiRt`ep IGAeJokmEeCtPr[yY. m1 m2 = \(\frac{1}{2}\) We can observe that the slopes are the same and the y-intercepts are different Answer: Question 34. Prove m||n 1 = 0 + c So, Consecutive Interior Angles Theorem (Thm. The given point is: (6, 1) From the given figure, REASONING We can observe that CRITICAL THINKING m1 m2 = -1 A bike path is being constructed perpendicular to Washington Boulevard through point P(2, 2). We know that, 1 + 138 = 180 The consecutive interior angles are: 2 and 5; 3 and 8. The angles are (y + 7) and (3y 17) m = 2 2x y = 18 1 and 8 are vertical angles Example 5: Tell whether the line y = {4 \over 3}x + 2 y = 34x + 2 is parallel, perpendicular or neither to the line passing through \left ( {1,1} \right) (1,1) and \left ( {10,13} \right) (10,13). Simply click on the below available and learn the respective topics in no time. The given equation is: 3 + 4 + 5 = 180 The equation of the line that is perpendicular to the given line equation is: = 4 b. m1 + m4 = 180 // Linear pair of angles are supplementary then they intersect to form four right angles. Bertha Dr. is parallel to Charles St. Answer: MATHEMATICAL CONNECTIONS So, y = -x + 8 y = 7 Answer: We can observe that Example 2: State true or false using the properties of parallel and perpendicular lines. 11 and 13 If the slope of two given lines are negative reciprocals of each other, they are identified as perpendicular lines. 7 = -3 (-3) + c c = 5 3 m = \(\frac{-30}{15}\) The equation that is perpendicular to the given line equation is: Substitute (-1, -1) in the above equation These Parallel and Perpendicular Lines Worksheets will ask the student to find the equation of a parallel line passing through a given equation and point. \(\frac{3}{2}\) . The angles that have the opposite corners are called Vertical angles x = 20 We know that, We can conclude that 4 and 5 angle-pair do not belong with the other three, Monitoring Progress and Modeling with Mathematics. Hence, from the above, We can observe that, Hence, from the above, Answer: In the same way, when we observe the floor from any step, The coordinates of y are the same. The line y = 4 is a horizontal line that have the straight angle i.e., 0 We know that, PROVING A THEOREM So, (x1, y1), (x2, y2) Measure the lengths of the midpoint of AB i.e., AD and DB. = \(\frac{50 500}{200 50}\) Tell which theorem you use in each case. Now, Answer: Hence, from the above, Slope of RS = 3, Slope of ST = \(\frac{3 1}{1 5}\) We get, Eq. Answer: Question 2. 8 6 = b To be proficient in math, you need to make conjectures and build a logical progression of statements to explore the truth of your conjectures. Think of each segment in the diagram as part of a line. To find the value of c, The adjacent angles are: 1 and 2; 2 and 3; 3 and 4; and 4 and 1 So, y = 3x + 9 Answer: Question 30. -2 \(\frac{2}{3}\) = c 3y 525 = x 50 For perpendicular lines, Answer: Question 20. We can observe that Answer: = \(\sqrt{(9 3) + (9 3)}\) Hence, from the above, This no prep unit bundle will assist your college students perceive parallel strains and transversals, parallel and perpendicular strains proofs, and equations of parallel and perpendicular. Now, The bottom step is parallel to the ground. = 2 (320 + 140) The given coplanar lines are: By using the Vertical Angles Theorem, Answer: Question 26. Answer: Question 14. Hence, In Exploration 2. find more pairs of lines that are different from those given. So, Slope (m) = \(\frac{y2 y1}{x2 x1}\) The coordinates of the subway are: (500, 300) We know that, (D) A, B, and C are noncollinear. { "3.01:_Rectangular_Coordinate_System" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.02:_Graph_by_Plotting_Points" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.03:_Graph_Using_Intercepts" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.04:_Graph_Using_the_y-Intercept_and_Slope" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.05:_Finding_Linear_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.06:_Parallel_and_Perpendicular_Lines" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.07:_Introduction_to_Functions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.08:_Linear_Inequalities_(Two_Variables)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "3.0E:_3.E:_Review_Exercises_and_Sample_Exam" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "01:_Real_Numbers_and_Their_Operations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "02:_Linear_Equations_and_Inequalities" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "03:_Graphing_Lines" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "04:_Solving_Linear_Systems" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "05:_Polynomials_and_Their_Operations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "06:_Factoring_and_Solving_by_Factoring" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "07:_Rational_Expressions_and_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "08:_Radical_Expressions_and_Equations" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "09:_Solving_Quadratic_Equations_and_Graphing_Parabolas" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "10:_Appendix_-_Geometric_Figures" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "zz:_Back_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "license:ccbyncsa", "showtoc:no", "authorname:anonymous", "licenseversion:30", "program:hidden" ], https://math.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fmath.libretexts.org%2FBookshelves%2FAlgebra%2FBeginning_Algebra%2F03%253A_Graphing_Lines%2F3.06%253A_Parallel_and_Perpendicular_Lines, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), Finding Equations of Parallel and Perpendicular Lines, status page at https://status.libretexts.org. Parallel to \(y=\frac{1}{2}x+2\) and passing through \((6, 1)\). Draw an arc by using a compass with above half of the length of AB by taking the center at A above AB Parallel lines are two lines that are always the same exact distance apart and never touch each other. 2x y = 4 3m2 = -1 Parallel and perpendicular lines are an important part of geometry and they have distinct characteristics that help to identify them easily. We can conclude that the given statement is not correct. We know that, We know that, y = x + 9 Slope (m) = \(\frac{y2 y1}{x2 x1}\) y = \(\frac{3}{2}\)x + 2 These guidelines, with the editor will assist you with the whole process. Now, y = \(\frac{1}{2}\)x + 2 So, Prove the statement: If two lines are horizontal, then they are parallel. Write an equation of a line perpendicular to y = 7x +1 through (-4, 0) Q. The coordinates of line 1 are: (-3, 1), (-7, -2) The line l is also perpendicular to the line j Now, We know that, Now, In this form, we can see that the slope of the given line is \(m=\frac{3}{7}\), and thus \(m_{}=\frac{7}{3}\). The points are: (-2, 3), (\(\frac{4}{5}\), \(\frac{13}{5}\)) 2x + y = 180 18 Two lines are cut by a transversal. Parallel lines are always equidistant from each other. The y-intercept is: 9. Explain why the tallest bar is parallel to the shortest bar. From the given figure, According to Corresponding Angles Theorem, The given figure is: The plane parallel to plane ADE is: Plane GCB. = \(\frac{9}{2}\) Answer: Question 24. Hence,f rom the above, Geometrically, we note that if a line has a positive slope, then any perpendicular line will have a negative slope. The equation that is perpendicular to the given line equation is: (7x + 24) = 108 The product of the slope of the perpendicular equations is: -1 Question 47. Slope of MJ = \(\frac{0 0}{n 0}\) PROOF Let us learn more about parallel and perpendicular lines in this article. (1) In Exercises 5-8, trace line m and point P. Then use a compass and straightedge to construct a line perpendicular to line m through point P. Question 6. Answer: We can conclude that the distance between the meeting point and the subway is: 364.5 yards, Question 13. Compare the given points with Answer: 15) through: (4, -1), parallel to y = - 3 4 x16) through: (4, 5), parallel to y = 1 4 x - 4 17) through: (-2, -5), parallel to y = x + 318) through: (4, -4), parallel to y = 3 19) through . All the Questions prevailing here in Big Ideas Math Geometry Answers Chapter 3 adhere and meets the Common Core Curriculum Standards. Proof of the Converse of the Consecutive Interior angles Theorem: a. Lets draw that line, and call it P. Lets also call the angle formed by the traversal line and this new line angle 3, and we see that if we add some other angle, call it angle 4, to it, it will be the same as angle 2. y = -3x + 150 + 500 The coordinates of line a are: (0, 2), and (-2, -2) The Parallel lines are the lines that do not intersect with each other and present in the same plane Alternate exterior anglesare the pair ofanglesthat lie on the outer side of the two parallel lines but on either side of the transversal line Cops the diagram with the Transitive Property of Parallel Lines Theorem on page 141. x 2y = 2 Hence, We can observe that 48 and y are the consecutive interior angles and y and (5x 17) are the corresponding angles Use the results of Exploration 1 to write conjectures about the following pairs of angles formed by two parallel lines and a transversal. y = 180 48 Slope (m) = \(\frac{y2 y1}{x2 x1}\) Hence. Question 1. We know that, Answer: The product of the slopes of the perpendicular lines is equal to -1 A1.3.1 Write an equation of a line when given the graph of the line, a data set, two points on the line, or the slope and a point of the line; A1.3.2 Describe and calculate the slope of a line given a data set or graph of a line, recognizing that the slope is the rate of change; A1.3.6 . Find an equation of the line representing the bike path. Hence, x = 14.5 and y = 27.4, Question 9. The equation that is parallel to the given equation is: So, Hence, We can observe that the given lines are parallel lines In Exercises 19 and 20, describe and correct the error in the reasoning. Answer: So, Slope (m) = \(\frac{y2 y1}{x2 x1}\) The given lines are: 4 and 5 are adjacent angles These worksheets will produce 6 problems per page. We can solve for \(m_{1}\) and obtain \(m_{1}=\frac{1}{m_{2}}\). So, 2 = 122 The are outside lines m and n, on . Perpendicular lines always intersect at 90. 1 = 80 We know that, The equation that is perpendicular to the given line equation is: When we compare the given equation with the obtained equation, c = -4 + 3 The two lines are Parallel when they do not intersect each other and are coplanar We know that, We can observe that Hence, The given point is: P (-8, 0) The portion of the diagram that you used to answer Exercise 26 on page 130 is: Question 2. y = \(\frac{1}{2}\)x + 8, Question 19. y = -2x + 8 Given Slope of a Line Find Slopes for Parallel and Perpendicular Lines Worksheets Slope of line 1 = \(\frac{9 5}{-8 10}\) By using the Perpendicular transversal theorem, To be proficient in math, you need to analyze relationships mathematically to draw conclusions. With Cuemath, you will learn visually and be surprised by the outcomes. Explain your reasoning. When we compare the converses we obtained from the given statement and the actual converse, The equation of the line along with y-intercept is: From the above definition, y = \(\frac{24}{2}\) The given point is: (4, -5) The distance wont be in negative value, Answer: a) Parallel to the given line: x + 73 = 180 The given figure is: Draw another arc by using a compass with above half of the length of AB by taking the center at B above AB Answer: The Alternate Interior Angles Theorem states that, when two parallel lines are cut by a transversal, the resultingalternate interior anglesare congruent From the given figure, y = -3 (0) 2 Substitute P (3, 8) in the above equation to find the value of c Hence, WRITING We can observe that E (-4, -3), G (1, 2) -2 3 = c Cellular phones use bars like the ones shown to indicate how much signal strength a phone receives from the nearest service tower. Answer: So, by the _______ , g || h. We get y = -3x 2 (2) Prove m||n We can conclude that the value of x when p || q is: 54, b. Verify your formula using a point and a line. The parallel line equation that is parallel to the given equation is: y = -2x + 3 We can observe that \(\overline{A C}\) is not perpendicular to \(\overline{B F}\) because according to the perpendicular Postulate, \(\overline{A C}\) will be a straight line but it is not a straight line when we observe Example 2 The theorem we can use to prove that m || n is: Alternate Exterior angles Converse theorem, Question 16. Hence, Examples of perpendicular lines: the letter L, the joining walls of a room. Hence, from the above, Think of each segment in the figure as part of a line. = 2.12 Answer:

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parallel and perpendicular lines answer key